ข้อสอบคณิต O-NET - 2561

$$\begin{gathered} \mathrm{จากโจทย์} \\ 3^{\left|x-4\right|} = {27}^{\frac{2}{3}} \end{gathered}$$

$$\begin{gathered} \mathrm{จะได้} 3^{\left|x-4\right|} = {\left(3^3\right)}^{\frac{2}{3}} \\ 3^{\left|x-4\right|} = 3^2 \\ \left|x-4\right| = 2 \\ x-4 = 2 , -2 \\ x = 2 , 6 \\ \mathrm{ดังนั้น} \mathrm{ผลบวกคำตอบ} = 2+6 = 8 \end{gathered}$$